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Chemistry 13 Online
OpenStudy (anonymous):

calculate the mass of NaOH required to prepare 2700mL of a 0.454M solution

OpenStudy (abhisar):

Hello @kajaraaaa ! \(\Huge{\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}\color{orange}{\bigstar}\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}\color{orange}{\bigstar}\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}}\\\color{white}{.}\\\Huge\sf\color{blue}{~~~~Welcome~to~OpenStudy!~\ddot\smile}\\\color{white}{.}\\\\\Huge{\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}\color{orange}{\bigstar}\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}\color{orange}{\bigstar}\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}}\)

OpenStudy (abhisar):

it will be 49.032 gm

OpenStudy (abhisar):

To prepare 2700 ml of 0.454M solution u will need \[0.454 X 2.7 = 1.22\] moles of NaOH

OpenStudy (abhisar):

now the molar mass of NaOH is 40. Just multiply it with 1.22 to get the mass required

OpenStudy (abhisar):

omit the minor calculation mistakes..if some

OpenStudy (anonymous):

thanks

OpenStudy (abhisar):

\(\Huge\text{Anytime !}\)

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