Question

(x=2)^2-9=0

Answer 1

\(\large\color{blue}{ \bf (x+2)^2-9=0 }\) This is the question. You didn't click shift and got + instead of +.

1) add 9 to both sides
2) take the square root of both sides (don't forget about ± )
3) finish the problem...

Answer 2

I mean got = instead of + ...

Answer 3

Simplify the quadratic and set it equal to 0.

x2+4x−5=0

Use the standard form of the quadratic (ax2+bx+c) to find a,b, and c for this quadratic.

a=1,b=4,c=−5

Use the quadratic formula to find the solutions.

\[x=\frac{ -b +- \sqrt{b^2 -4ac} }{ 2a }\]

Substitute in the values of a=1,b=4, and c=−5.

\[x=\frac{ -4 +- \sqrt{(4^2 -4(1)(-5)} }{ 2(1) }\]

Simplify the discriminant.

x=−4 ± 62(1)

Simplify the denominator.

x=−4 ± 62

Solve the + portion of ±,(−4+6)(2).

x=1

Solve the − portion of ±,(−4−6)(2).

x=−5

The final answer is the combination of both solutions.

x=1,−5

Answer 4

Ewww... quadratic formula?? It's so much simpler than that !

Answer 5

Ewww... quadratic formula?? It's so much simpler than that !