Question

Factor completely: 2x^3 + 4x^2 + 6x + 12

2(x^3 + 2x^2 + 3x + 6)

(2x^2 + 6)(x + 2)

2[(x^2 + 2)(x + 3)]

2[(x^2 + 3)(x + 2)]

Answer 1

2x^3 + 4x^2 + 6x + 12
2(x^3 + 2x^2 + 3x + 6)
2[(x^3 + 2x^2)(3x + 6)]
2[x^2(x + 2) 3(x + 2)]
2[(x^2 + 3)(x + 2)]
D is the answer. Do you understand how I did that?

Answer 2

no

Answer 3

I factored by grouping.

Answer 4

First, take out the GCF. In this case in is two.
Then, put the remaining number into groups of two: (x^3 + 2x^2) and (3x + 6).
Next, factor out the factors of the groups. The groups still left in parentheses should be the same: (x + 2) and (x + 2).
Last, put the outside number in parentheses (x^2 + 3) and put it all together:
2[(x^2 + 3)(x + 2)]
Now do you get it?

Answer 5

medal...