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OpenStudy (anonymous):
The charge of a vanadium ion in the compound V2O5 is: A.10- B.2+ C.5+ D.10+ E.none of the above
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OpenStudy (anonymous):
ok, so we know that O almost always has a (-2) charge.. On V2O5 you have 5 oxygen, the over all charge on V2O5 is neutral. What must be the charge on V if you have 2 of them?
OpenStudy (anonymous):
You could also do this algebraically if you wish => 2(x)+5(-2)=0 solve for x
OpenStudy (anonymous):
I believe it is +5
OpenStudy (anonymous):
Yep!
OpenStudy (anonymous):
I posted another question: How many electrons would be in a -2 charged anion of sulfur?
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