Question

I need help with algebra 2 o:

Answer 1

The ask away!

Answer 2

hi :DDD

Answer 3

Ok, to solve these type of problems, you need to first first get rid of the "log" part of the equation. You do this by setting the right side of the equals sign as the power over the number the log is put to. (9, in this case). This leaves us with:\[x=9^(3/2)\]

Answer 4

Then, simplify.

Answer 5

Wait... So 3/2^9 or?

Answer 6

Oh, for some reason it put the "3/2" on the same level as the nine. It should say 9^(3/2).

Answer 7

So.. 364.5?

Answer 8

How are you getting that?

Answer 9

I thought I logged each side?

Answer 10

No, we got rid of the log when we made it "x=9^(3/2)"

Answer 11

So the answer is 364.5

Answer 12

How are you getting that? It's much too high.

Answer 13

182.25 sorry haha.

Answer 14

Again, just tell me how you got that.

Answer 15

i pressed 9 to the square root of 3/2 in the calculator:)

Answer 16

Wait it's 27!

Answer 17

Why square root it? Isn't it an exponent?

Answer 18

Correct.

Answer 19

Any others you need help with?

Answer 20

Yes sorry I was doing some I knew:)

Answer 21

Ok, to start, tell me what the product is of the two fractions inside of the square root signs. Ignore the square root part for now.

Answer 22

.75

Answer 23

Actually, I found a simpler way. Instead of what I just said, start by simplifying the second radical's division problem first.

Answer 24

So .75 square rooted

Answer 25

Don't divide the fraction, keep it as is. But, yes, that's it. Now, notice the two fractions now. What's similar about them now?

Answer 26

They are equivalent.

Answer 27

Exactly! So, when multiplying two of any value (when both are the same), if that value is "x", then the answer is "x^2". So, what's the new value when you multiply the square-rooted fractions?

Answer 28

uhm... I'm not sure.

Answer 29

1 1/2?

Answer 30

I'd leave it as 3/2, but yes, you're correct.

Answer 31

So 3/2 is the answer?

Answer 32

Yep! But what you said was simply another way of stating 3/2.

Answer 33

Yes:)

Answer 34

Any others?

Answer 35

Ok, looking back on what we were working on previously, I mentioned that we have to switch two parts, and drop one. Which ones were those?

Answer 36

The 3 and 729?

Answer 37

Be more specific please. Try your best to restate the equation after moving stuff around.

Answer 38

Wouldn't it be x= 3^729?

Answer 39

No, that'd turn out much larger than it should be. I'll make a quick illustration to show how to move stuff.

Answer 40

3^?=729

Answer 41

Yep! Now, there is probably a better method, but I just put in a number into the calculator to represent the power 3 is put to until I found the one resulting in 729. See if you can find what power that is.

Answer 42

x=6

Answer 43

Correct!

Answer 44

Any more?

Answer 45

Ok, to start, let's get rid of the squareroot on the right side. Any idea how that's done? If not, then think of this: what's the opposite function (the one that cancels out) of square-rooting something?

Answer 46

I honestly have no idea with this one.

Answer 47

How did we remove the square root from the "sqrt(3/2)" a little earlier? What was done to that that left us with just the 3/2?

Answer 48

square rooted it?

Answer 49

No, look back. What was added to the "sqrt (3/2)" when it was multiplied by itself to leave it with just 3/2?

Answer 50

Something to do with a log? Idk....

Answer 51

Hmm, I'll write you a little guide for opposites of functions (for future use).

Answer 52

So, given this, how do you remove a square root from one side of an equation? Keep in mind that what is done to one side must be done to the other.

Answer 53

Exponent of same value as the root.