Question

solve for x: 9^2x=27

Answer 1

One way to do this is to get each base equal to the same number (in this case, we can get them both equal to 3 since 9 = 3^2 and 27 = 3^3)


\[\Large 9^{2x} = 27\]


\[\Large (3^2)^{2x} = 3^3\]


\[\Large 3^{2*2x} = 3^3\]


Do you see what to do from here?

Answer 2

not really

Answer 3

The two sides are equal. In order for that to be true, the exponents must be equal (since the bases are equal to 3)

Answer 4

So that means 2*2x = 3

now solve for x

Answer 5

oh okay thank you

Answer 6

you're welcome