Question

I need help, please help
an object starts from rest at time t=0 and moves in the x direction with constant acceleration. The object travels 12m from time t=1 to time t=2. what is the acceleration of the object?

Answer 1

Is the answer 24ms^-2

Answer 2

Since the object starts from rest, you can express it's initial velocity in the period between t=1 and t=2 in terms of the acceleration:
\[v(t) = v_0 + a*\Delta t\]
\[v(1) = 0 +a*1 = a\]
and substitute this result to the x(t) position equation:
\[x(\Delta t) = v_0*\Delta t + 0.5*a*\Delta t^2 \]
\[x(1->2) = a*1 + 0.5*a*1 = 1.5*a = 12\]
and from here you get:
\[a = 8 (m/\sec^2)\]

Answer 3

Thank you Elb27 for your help