Question

Help solving a derivative please? <3

f(g)= 2g^2(3g^3-g^2-4g+1)

I'm not sure which power to use... I have a feeling it has something to do with the sum and difference rule which I'm struggling with. Please explain?

Answer 1

I would distribute 2g^2, then take derivative if I were you.

Answer 2

I'm thinking just using the product rule and power rule would do

Answer 3

Or you can use chain rule. Both work.

Answer 4

you just really have 2 functions multiplying each other

Answer 5

Well, both contains same variable and one of these function only has one term, so you can easily distribute it.

Answer 6

though @geerky42 is correct, if you distribute first, since all variables are the same, the exponents will just sum up

Answer 7

The answer is supposedly f'(g)=30g^4-8g^3-24g^2+49 so I don't think you are only supposed to distribute...

Answer 8

I'm sure this is not answer to this question.

Answer 9

It's in my book... :p

Answer 10

Well, it is not correct. Try to check again? Or is there more information we need to know?

Answer 11

Is most definitely is the answer

Answer 12

\(\bf f(g)= 2g^2(3g^3-g^2-4g+1)
\\ \quad \\
\implies f(g)=2g^23g^3-2g^2g^2-2g^24g^1+2g^2
\\ \quad \\
\implies 6g^{2+3}-2g^{2+2}-2g^{2+1}+2g^2\)

Answer 13

then you simply use the power rule for each term

Answer 14

but yes, distributing first would work fine

Answer 15

No, it's not right answer, @marissalovescats

Answer 16

I'm just unsure how they have a 49 at the end and not +4g

Answer 17

Ahhh @Marissalovescats Thank you!!!! And to @jdoe001 too for leading up to it! :)

Answer 18

Oh gosh it definitley is a 4g... my mistake

Answer 19

Thank you!!! <3

Answer 20

yw

Answer 21

Marissa, not sure where your response went but I'm just going to choose one of your comments as the best answer haha :)