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Mathematics 9 Online
OpenStudy (anonymous):

Which of the following tables shows the correct steps to transform x^2 + 10x + 24 = 0 into the form (x - p)^2 = q? [p and q are integers]

OpenStudy (anonymous):

OpenStudy (anonymous):

@jdoe0001

OpenStudy (jdoe0001):

do you know what a perfect square trinomial is?

OpenStudy (anonymous):

Isn't that where you can't factor it more?

OpenStudy (jdoe0001):

well... not quite..... a perfect square trinomial would be \(\bf a^2\pm2ab+b^2\iff (a\pm b)^2\\ \qquad \uparrow \\ \textit{perfect square trinomial}\)

OpenStudy (jdoe0001):

TRInomial, tri=three terms

OpenStudy (jdoe0001):

lemme give you a quick example \(\bf (3x+2y)^2\implies (3x)^2+2\cdot 3x\cdot 2y+(2y)^2\) see the correspondence to the squared binomial?

OpenStudy (anonymous):

i see it would the answer be D

OpenStudy (jdoe0001):

well... what makes you think is D?

OpenStudy (anonymous):

what makes me think D is because i know that a and b are wrong because they don't use the same equation from the question and i don't think it is C because of teh double parentheses so by that process it makes me think D

OpenStudy (anonymous):

*the

OpenStudy (anonymous):

@jdoe0001

OpenStudy (jdoe0001):

I think the parentheses is just a typo and they all use the same equation to start off from

OpenStudy (anonymous):

oh wait sorry i just realized that my reasoning is wrong when i looked at it again

OpenStudy (anonymous):

Did i get it right anyway with D?

OpenStudy (jdoe0001):

so let's try to "complete the square" \(\bf x^2 + 10x + 24 = 0\implies x^2 + 10x =-24\implies (x^2 + 10x) =-24 \\ \quad \\ (x^2 + 10x+{\color{red}{ \square }}^2) =-24\) so what do you think would be a number that would "complete the " perfect square trinomial?

OpenStudy (jdoe0001):

recall \(\bf \Large \bf a^2\pm2ab+b^2\iff (a\pm b)^2\)

OpenStudy (jdoe0001):

and that our perfect square trinomial is \(\bf \Large \bf a^2\pm2ab+b^2\)

OpenStudy (anonymous):

so 2?

OpenStudy (jdoe0001):

well. 2 there is just part of the template not a value for "a" or "b"

OpenStudy (anonymous):

10?

OpenStudy (jdoe0001):

well, 2 * a * b or 2 * first term * 2nd term = 10x we know the first term, is "x" we dunno the 2nd term but we know that 2 * first term * 2nd term = 10x 2 * x * 2nd term = 10x so \(\bf 2\cdot x\cdot {\color{red}{ \square }}=10x\) so what do you think is our 2nd term?

OpenStudy (anonymous):

24

OpenStudy (jdoe0001):

24 ok let's see 2 * x * 24 = 10x? well 2 * x * 24 = 2 * 24 * x => 48x so.. is not 24 though

OpenStudy (anonymous):

5

OpenStudy (anonymous):

2 * x * 5 = 10x

OpenStudy (jdoe0001):

5 let's try that one 2 * x * 5 = 10? 2 * x * 5 => 2 * 5* x => 10x yes so now we know that our 2nd term is 5 in the perfect square trinomial thus we would ADD that to the equation keep in mind that all we're doing is borrowing from mr zero, 0, our good friend so if we ADD \(5^2\) we have to also SUBTRACT \(5^2\) thus \(\bf x^2 + 10x + 24 = 0\implies x^2 + 10x =-24\implies (x^2 + 10x) =-24 \\ \quad \\ (x^2 + 10x+{\color{red}{ 5 }}^2)-{\color{red}{ 5 }}^2 =-24\implies (x+5)^2-25=-24 \\ \quad \\ (x+5)^2=-24+25\implies (x+5)^2=1\)

OpenStudy (anonymous):

so that means that the answer is d right?

OpenStudy (jdoe0001):

notice that to "complete the square" all we really needed was 25 and we started off with 24 so we really could have just added +1 :) \(\bf x^2 + 10x + 24 = 0 \\ \quad \\ x^2 + 10x + 24 +1= 0+1 \\ \quad \\ x^2 + 10x +25=1\implies (x+5)^2=1\) yeap

OpenStudy (anonymous):

thanks

OpenStudy (jdoe0001):

yw

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