Question

What is the equation in point-slope form of the line passing through (−2, 0) and (2, 8)?

Answer 1

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ -2}}\quad ,&{\color{blue}{ 0}})\quad &({\color{red}{ 2}}\quad ,&{\color{blue}{ 8}})
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}
\\ \quad \\

y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values}\\
\qquad \uparrow\\
\textit{point-slope form}\)

Answer 2

oh k thank u

Answer 3

yw

Answer 4

is the answer will be y = −2(x − 2)

Answer 5

need help

Answer 6

It depends on which point you chose to use. I'm guessing you chose (0,-2) ?

Answer 7

Sorry (-2,0) lol

Answer 8

Remember that two negatives equal a positive.

Your slope would be 2 because:

8-0/2-(-2) = 8/4= 2

So if you used the point (-2,0)

y-0=2(x-(-2)

y-0=2(x+2)

y=2x+4

Answer 9

You could use the other point as well (2,8)

y-8=2(x-2)

y-8=2x-4

y=2x+4

Answer 10

oh k this are the answers
y = 2(x + 2)

y = 2(x − 2)

y = −2(x − 2)

y = −2(x + 2)

Answer 11

Well it would be y=2(x+2) because when you distribute the 2 you get y=2x+4

Answer 12

oh k thank u

Answer 13

You're welcome.