Question

PLEASE HURRY!

Answer 1

What are the x intercepts of the quadratic function y=x^2 - x - 2

Answer 2

A. 2 and 1
B.-2 and 1
C.2 and -1
D.1

Answer 3

It's C. Just factor it into (x + 1)(x -2). They are both set to = 0, so x + 1 = 0, solve for x; x - 2 = 0 so x = 2.

Answer 4

What about y=-x^2 + 2x - 1

A. 2 and 1
B. -2 and 1
C 2 and -1
D 1

Answer 5

Ok, this answer is D. Let's do this one step by step. The first thing to do is to factor out the -1 to get \[-(x ^{2}-2x+1)\]When you factor this you get \[-(x-1)(x-1)=0\]Since you have two solutions the same you only need to solve one of them because their solutions are the same. So \[-(x-1)=0-->-x+1=0\]I distributed the negative back in; do you see that step? Get it? Now solve for x. -x = -1 or x = 1.