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What is the period? y=cos(3x)
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@IMStuck maybe you could help me?
For a periodic function of the form \(\sin bt\) or \(\cos bt\), the period is \(\dfrac{2\pi}{b}\).
okay and be in this case would be 3?
That's the value of \(b\), yes.
Ok, in order to find the period of a function, you have to remember what the original period of the function is. For cosin, the whole thing happens in 2pi. Right? In order to find the period of that (it's a double angle), you divide 2pi by 3 (the 3 is from your (3x). So the new period is 2pi/3.
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okidoki thank you thank you
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