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Find the surface area of a cylinder with a base area of 49 Π in2 and a height that is twice the radius of its base.
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Surface Area of a cylinder is given by (Area of the Bases) + (Lateral Area). They told us the Area of the base is \(\Large\rm 49\pi\). Let's match this up with the formula we know for area of a circle.\[\Large\rm A=\pi r^2\qquad\to\qquad 49\pi=\pi r^2\]What do we get for our radius?
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k
is the radius 7?
Mmm yes good.
i think the answer is \[294\], right?
\[294\pi \]
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in ^2
Mmmm yah that's what I'm coming up with! Yay good job \c:/
ty!!
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