A sphere with radius 14 km is cut by a plane that is 6 km above its center. Give an approximation of the area of the circle formed by the intersection of the plane and the sphere. http://i.imgur.com/kcXedHC.png Which formula should be used to solve this? **Options in picture** http://i.imgur.com/iW7uWCT.png ( i think its D is that correct) What is the formula for the Surface Area of a Pyramid? (I think its C is that correct?) http://i.imgur.com/4eGxKmt.png
for the first question, use the pythagorean theorem. for the second, I believe you are correct.
Could you show me how to use it? Thats were I always fail, or the equation?
so you have a right triangle with side lengths r, x, and y. do you know the length of r? do you know the length of x? do you know the length of y?
No i don't know any of the measurements
really? think again. what numbers are you given?
14 and 6
what is 14? does it happen to be r, x, or y? what is 6? does it happen to be r, x, or y?
Im not sure is 14 x?
is 6 y?
no... what is 14?
the radius of the sphere
ok. look on the picture. what letter represents the radius of the sphere?
Im not sure i thought the point for x did
it's r. look at the image lol, r goes from the center of the sphere to a point on the sphere, so it is the radius by definition
x isn't the point, x is a label for one of the line segments
oh my I told you Im horrible gahh
you're fine lol. but anyways, let's see if we can figure out what the number 6 means
So, 14 is r, is 6 y?
careful. 6 is the distance the plane is above the center of the sphere, correct?
oh yes
so would it be x.... Im guessing
yup. since x in this image is the distance from the center the plane is.
so with the pythagorean theorem, what can we deduce?
that a2+b2+c2, but i don't now how to put them into the equation
=c2 i meant
yeah. so just know that a and b are the legs , and c is the longest side or hypotenuse (which is opposite the 90 degree angle). so can you figure out how to put the numbers into the equation?
6^2+y^2=14^2?
yes.
so solve for y, and we have the radius of the circle
btw when I said your second formula was correct I acutally meant your third.
Oh okay i was like waaattt :)
Im don't know how to solve it to be honest with you... :(
I*
well, 6^2+y^2=14^2 now simplify as much as you can 36+y^2=196 isolate the variable y^2=160 now find the square root y=sqrt(160) a negative square root makes no sense for length, so we take the positive. simplify the radical \(\Huge y=4\sqrt{10}\)
@inkyvoyd you are an angel
that is also why i can't see you im guessing, don't lie
thanks :) anyways note that that's the radius, and you need the actual area of the circle
Oh lol, i always do that , always ugh. So, now what?
take A=pi*r^2; you already found r=4sqrt(10). and for the second part, just put in the values for r and x and see which one works out to the answe ryou get for the area. I got B for the second
so the equation is A=3.14*4sqrt(10)^2?
yes but makes ure the 4sqrt(10) is in parenthesis cause it's the whole thing that's the radius
anyways, I think you should be able to get the rest... I must sleep. good luck!
Okay, thank you so much, have a nice night!!
you too :)
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