Ask your own question, for FREE!
Physics 9 Online
OpenStudy (anonymous):

Someone please explain how to do this MCQ.

OpenStudy (anonymous):

OpenStudy (mrnood):

|dw:1401709554674:dw| First of all consider the 2 resistors in Parallel (6 and 3) Work out the equivalent resistance of just those 2 THEN you have the 2 ohm + the 'equivalent resistance' in series, so you can work out the total resistance. Then you have V , you have total resistance I - V/R so you can calculate the current

OpenStudy (anonymous):

@MrNood : The answer is 1.0A. I'm not getting it by this method. O.o

OpenStudy (anonymous):

This is a question from Cambridge International Examination. Their official marking scheme says 1.0A. >_<

OpenStudy (mrnood):

OK - I'm sorry - I didn't read the question properly

OpenStudy (mrnood):

My answer was for the total current - I didn't see that I refers to current through the 6ohm resistor only

OpenStudy (mrnood):

Using my answer you can see that the parallel resistors are equivalent to 2ohms since the other resistor is also 2 ohms the voltage between the 2ohm and th eparallel must be 6V Therefore you have 6V across a 6 ohm resistor -> 1 amp

OpenStudy (anonymous):

Oh, got it now. Thank youuu so much. ^_^

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!