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Mathematics 25 Online
OpenStudy (anonymous):

For the graphed function f(x) = (4)x - 1 + 2, calculate the average rate of change from x = 2 to x = 4.

OpenStudy (anonymous):

OpenStudy (anonymous):

@johnweldon1993

OpenStudy (anonymous):

@ganeshie8 ...

ganeshie8 (ganeshie8):

the asked question and the picture u attached are not matching

ganeshie8 (ganeshie8):

check once..

OpenStudy (anonymous):

okay sorry, just click the picture then...

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

how?

ganeshie8 (ganeshie8):

average rate of change from x = 2 to x = 4 is \(\large \dfrac{f(4) - f(2)}{4-2}\)

ganeshie8 (ganeshie8):

first find f(4) and f(2)

ganeshie8 (ganeshie8):

\(\large f(x) = 4^{x-1}+2\)

ganeshie8 (ganeshie8):

plugin x = 4 for f(4)

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

would 4 be the exponent?

ganeshie8 (ganeshie8):

\(\large f(4) = 4^{4-1}+2 = 4^3 + 2 = 64 + 2 = 66\)

ganeshie8 (ganeshie8):

similarly find f(2) and plug them in the average rate of change formula

OpenStudy (anonymous):

okay, would i subtract the answers?

ganeshie8 (ganeshie8):

yes, and then divide by 4-2

ganeshie8 (ganeshie8):

\(\large f(2) = 4^{2-1}+2 = 4^2 + 2 = 4 + 2 = 6\)

OpenStudy (anonymous):

30

OpenStudy (anonymous):

right?

ganeshie8 (ganeshie8):

30 is right !

OpenStudy (anonymous):

Thank you :) can you help me with another

OpenStudy (anonymous):

@ganeshie8

ganeshie8 (ganeshie8):

sure, ask

OpenStudy (anonymous):

ganeshie8 (ganeshie8):

\[\large \log_{2x-5} 25 = 2\] \[\large \log_{2x-5} 5^2 = 2\] \[\large 2\log_{2x-5} 5 = 2\] \[\large \log_{2x-5} 5 = 1\]

ganeshie8 (ganeshie8):

change it to exponent form

ganeshie8 (ganeshie8):

\[\large 5 = (2x-5)^1\]

ganeshie8 (ganeshie8):

solve \(x\)

OpenStudy (anonymous):

I got 5... is that right

ganeshie8 (ganeshie8):

5 is right !!

OpenStudy (anonymous):

wow thanks! i have 2 more is that okay?

OpenStudy (anonymous):

ganeshie8 (ganeshie8):

wat do u think the equation is

OpenStudy (anonymous):

the first one?

ganeshie8 (ganeshie8):

right !

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

that's the right answer?!

OpenStudy (anonymous):

i have one more!

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

i think it's the second one actually.

OpenStudy (anonymous):

@ankit042 the most recent one!

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