Solve the equation.
= 5
A.
x = -4
B.
x = -12
C.
x = -20
D.
x = -28
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OpenStudy (anonymous):
@mathshelp14
OpenStudy (anonymous):
plz help @e.mccormick
OpenStudy (e.mccormick):
Something is missing.
OpenStudy (anonymous):
oh yeah just a minute
OpenStudy (anonymous):
. PREALG4M 3.3.1-15+
Solve the equation.
= 5
A.
x = -4
B.
x = -12
C.
x = -20
D.
x = -28
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OpenStudy (anonymous):
is that what was missing?
OpenStudy (e.mccormick):
Nope.
=5 is not an equation. It is half of one.
OpenStudy (anonymous):
no no n o n just a minute
OpenStudy (anonymous):
PREALG4M 3.3.1-15+
Solve the equation.
= 5
OpenStudy (anonymous):
it wont show the other side
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OpenStudy (e.mccormick):
Well, type it.
OpenStudy (anonymous):
x/-4
OpenStudy (anonymous):
but its supposed to go up and down
OpenStudy (e.mccormick):
\(\dfrac{x}{-4}=5\)
OpenStudy (anonymous):
yeah
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OpenStudy (e.mccormick):
OK. So, what can you multiply both sides by to get the -4 over to the right of the =?
jaynator495 (jaynator495):
the answer is x=-20 because scince there both negative... its like deviding 4 by 20 which is 5 so -4/-20=5
i hope this helped ;), -Jaynator495
OpenStudy (anonymous):
um
OpenStudy (anonymous):
thank you
jaynator495 (jaynator495):
your welcome ;)
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OpenStudy (e.mccormick):
This is the process I was trying to get you to see:
\(\dfrac{x}{-4}=5\)
\(\dfrac{-4}{1}\cdot\dfrac{x}{-4}=5\cdot\dfrac{-4}{1}\)
\(\dfrac{\cancel{-4}}{1}\cdot\dfrac{x}{\cancel{-4}}=\dfrac{(5)\cdot(-4)}{1}\)
\(x=\dfrac{-20}{1}\)
\(x=-20\)
The key is that multiplication and division undo each other. So when you have a division question, you can use multiplication to both sides to undo it and find the answer or a step towards the answer.