Solve the equation. = 5 A. x = -4 B. x = -12 C. x = -20 D. x = -28
@mathshelp14
plz help @e.mccormick
Something is missing.
oh yeah just a minute
. PREALG4M 3.3.1-15+ Solve the equation. = 5 A. x = -4 B. x = -12 C. x = -20 D. x = -28
is that what was missing?
Nope. =5 is not an equation. It is half of one.
no no n o n just a minute
PREALG4M 3.3.1-15+ Solve the equation. = 5
it wont show the other side
Well, type it.
x/-4
but its supposed to go up and down
\(\dfrac{x}{-4}=5\)
yeah
OK. So, what can you multiply both sides by to get the -4 over to the right of the =?
the answer is x=-20 because scince there both negative... its like deviding 4 by 20 which is 5 so -4/-20=5 i hope this helped ;), -Jaynator495
um
thank you
your welcome ;)
This is the process I was trying to get you to see: \(\dfrac{x}{-4}=5\) \(\dfrac{-4}{1}\cdot\dfrac{x}{-4}=5\cdot\dfrac{-4}{1}\) \(\dfrac{\cancel{-4}}{1}\cdot\dfrac{x}{\cancel{-4}}=\dfrac{(5)\cdot(-4)}{1}\) \(x=\dfrac{-20}{1}\) \(x=-20\) The key is that multiplication and division undo each other. So when you have a division question, you can use multiplication to both sides to undo it and find the answer or a step towards the answer.
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