Prove: tan^2 θ cos^2 θ + cos^2 θ = 1. You must show all work.
Hint: Factor out \(\cos^2\theta\)
How do I do that?
After factoring out \(\cos^2\theta\) you should have \(\cos^2 \theta (\tan^2 \theta + 1) = 1\)
Next divide both sides by \(\cos^2\theta\)
tan^2x=sin^2x/cos^2x cosines cancel and you get an identity.
Or you can do that which would be better. @SolomonZelman just couldn't help himself.
I don't really understand the last sentence of your comment :) -:(
@SolomonZelman Can you help with one more
When I "help" myself, posting the solution and answer, I get suspended. So why would I do that ?
Gamer, Perhaps I can:) I'll try to flex my weak brains.
I did a problem like that before with you but I seem to have forgot it @SolomonZelman
attach not working -:(
Actually, it would have been better to divide both sides by \(\cos^2 \theta\) because then you would have seen that \(\tan^2\theta + 1 = \sec^2 \theta\)
@Hero Can you please help"?
At that point you could have done this: \(\cos^2\theta(\sec^2\theta) = 1\)
And since you know that \(\sec^2\theta = \dfrac{1}{\cos^2\theta}\) You could have written it this way for the next step: \(\cos^2\theta\left(\dfrac{1}{\cos^2\theta}\right) = 1\)
@Hero Help with my other question
Can you??
Yes, but post it as a new question
Sure but don't leave
Try your best to post only one question at a time. Don't post two questions in the same discussion unless they are purposefully related to each other. Like for example Part A, and Part B, of Question 1
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