A quadratic function is much easier to graph when written in the following form.
y = a(x - h)2 + k
To convert an equation from the form y = ax2 + bx + c into the form y = a(x - h)2 + k use completing the square.
What does the equation y = x2 - 10x + 5 become after completing the square?
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OpenStudy (thefluffmuncher):
how do i do this?
OpenStudy (anonymous):
\[y = x^2 - 10x + 5 \] you want to write it as
\[y=a(x-h)^2+k\] right?
OpenStudy (thefluffmuncher):
yes
OpenStudy (anonymous):
it should be clear that \(a=1\) because you are starting with \(x^2\) and not for example \(2x^2\) in which case you would have \(a=2\) so it must look like
\[y=(x-h)^2+k\]
OpenStudy (anonymous):
then it is easy
what is half of \(-10\) ?
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OpenStudy (thefluffmuncher):
-5?
OpenStudy (anonymous):
lol yes
so it is '
\[y=(x-5)^2+k\]
OpenStudy (anonymous):
to find \(k\) put \(5\) for \(x\) in
\[y=x^2-10x+5\] i.e. compute
\[5^2-10\times 5+5\] and that will give you \(k\)
OpenStudy (anonymous):
let me know when you get \(k=-20\)
OpenStudy (thefluffmuncher):
i got -20 already
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