A quadratic function is much easier to graph when written in the following form. y = a(x - h)2 + k To convert an equation from the form y = ax2 + bx + c into the form y = a(x - h)2 + k use completing the square. What does the equation y = x2 - 10x + 5 become after completing the square?
how do i do this?
\[y = x^2 - 10x + 5 \] you want to write it as \[y=a(x-h)^2+k\] right?
yes
it should be clear that \(a=1\) because you are starting with \(x^2\) and not for example \(2x^2\) in which case you would have \(a=2\) so it must look like \[y=(x-h)^2+k\]
then it is easy what is half of \(-10\) ?
-5?
lol yes so it is ' \[y=(x-5)^2+k\]
to find \(k\) put \(5\) for \(x\) in \[y=x^2-10x+5\] i.e. compute \[5^2-10\times 5+5\] and that will give you \(k\)
let me know when you get \(k=-20\)
i got -20 already
k then you are done it is \[y=(x-5)^2-20\]
ty so much!!!
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