Question

f(t) = 1000e^0.2. Find f^-1(p)

Answer 1

I know this is a log problem

Answer 2

shuold there be a t in there somewhere?

Answer 3

oh, yeah

Answer 4

else it does not make sense

Answer 5

1000e^0.2t

Answer 6

so f(x)= 1000e^(0.2t)
y = 1000e^(0.2t)
we need to find the inverse
y/1000 = e^(0.2t)
ln(y/1000) = ln(e^(0.2t))
ln(y/1000)=0.2tln(e) = 0.2t
so
t = ln(y/1000)/0.2

Answer 7

so when I solve the problem, do I substitute p in for y?

Answer 8

since it is f^-1(p)

Answer 9

@zzr0ck3r

Answer 10

before just used x and y

Answer 11

yes