A farmer wishes to enclose two rectangular pens with fencing, as shown in the figure below. If the farmer has 400 feet of fencing to use, what is the maximum area he can enclose?

Question

A farmer wishes to enclose two rectangular pens with fencing, as shown in the figure below.  If the farmer has 400 feet of fencing to use, what is the maximum area he can enclose?

anonymous · Answer

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anonymous · Answer

A = x(400 - 2x)
A = 400x - 2x^2
A(x) = -2x^2 + 400

-b/2a = -400/2(-2) = -400/-4 = 100

400 - 2(100) = 400 - 200 = 200

A = 100 * 200 = 20000 ft^2

anonymous · Answer

I think I might be missing something

anonymous · Answer

@mathslover @goformit100 @ganeshie8

anonymous · Answer

make both pens square and all sides equal there are 7 sides
7*s = 400 
s = 400/7
Area = 2* area of each square = 2* (400/7)^2

anonymous · Answer

^ ?

anonymous · Answer

you can turn rectangle into squere only under certain conditions,like width being twice of height

anonymous · Answer

umm okay
see

anonymous · Answer

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