Ask your own question, for FREE!
Physics 11 Online
OpenStudy (anonymous):

Using Graph B: http://www.webassign.net/sercp8/2-figure-07.gif Find the average and instantaneous velocity at t = 9.3 s. Got -0.75 m/s for average velocity, not at all positive that's correct. (To be able to view graph, copy and paste the link! Clicking it won't work :( )

OpenStudy (anonymous):

By this graph (b) the region near t=9.3 is linear (i.e. straight line). Thus, the velocity in this region is constant and can be found by calculation the slope of the line BC: \[v_(average) = v(insta.) = (0-10)/(12-8) = -2.5(m/\sec)\]

OpenStudy (anonymous):

Thanks again!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Arriyanalol: i need help
2 days ago 7 Replies 1 Medal
Arriyanalol: CONGRATS to me
2 days ago 8 Replies 2 Medals
Legomaster346: What colleges are good that are near Arab Alabama?
1 week ago 5 Replies 0 Medals
Arriyanalol: i need help
1 week ago 6 Replies 2 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!