Question

Name the x-values for which the sine function and the cosine function equal to zero simultaneously in the domain 0°< x < 360°

Name the x-values for which the tangent function is undefined in the domain 0°< x < 360°. Explain why the tangent function is undefined at those x-values.

Answer 1

A. GRAPHS OF THE TWO BASIC FUNCTIONS: SINE and COSINE y=sinx 1 ... Period - length of the smallest domain interval which corresponds to a complete ... amplitude = I a | = 3 The function has a maximum y value of 3. 2 2 ... denominator, cos x, equal to zero (to avoid division by zero). Thus, for ... 0 for these x values

Answer 2

@ikatouni ok i'm confused lol. what would our answer be?

Answer 3

Identify the domain and range of the six basic trigonometric functions. .... Just like sin(x), the x-values never "escape" from the unit circle, so they stay between −1 and 1. ... The name of the tangent function comes from the tangent line, which is a line .... First of all, at 0° itself, the cotangent is undefined because the segment is

Answer 4

I definitely agree with @ikatouni Good job

Answer 5

did u find what the segment is that ur answer

Answer 6

@ikatouni no i don't know how :( i'm not sure how to find the answer.

Answer 7

do u have any answer choices

Answer 8

@ikatouni no :( i wish i did lol

Answer 9

can u just tell me the answer for the two questions? please?

Answer 10

The graph repeats itself because the cotangent function is periodic

Answer 11

that's the answer

Answer 12

for both?

Answer 13

Through Quadrant I that height gets larger, starting at 0 .... itself, the cotangent is undefined because the segment is parallel to the ray
the other one

Answer 14

oh thats the answer for the second one?

Answer 15

but it says name the x-values? what are the x-values?

Answer 16

Recall from Trigonometric Functions, that `tan x` is defined as: ... `0` in the denominator of the fraction and this means the fraction is undefined. ...

Answer 17

@nipunmalhotra93 do you know the answers?

Answer 18

I just gave it to u ^^

Answer 19

@veraewing There's no x for which both sinx and cosx are 0. One of the explanations for that could be that (sinx)^2+(cosx)^2=1 for all x. So both being 0 is not possible.
tan=sin/cos. So, it'll be undefined at all those points where cos is 0. So the answer for part b is 90 and 270.