Question

PLEASE HELP! I'm ALMOST done and I just need help on this one question... Attachment below!!!

Answer 1

@amistre64

Answer 2

@amistre64 Hey, man! I am on this one test and I'm trying to get done with it, could you help me on this problem?

Answer 3

\[ \frac{2x^2-6x}{x^2+18x+81}\div\frac{x^2-9}{x^2-81}\\
=\frac{2x^2-6x}{x^2+18x+81}\times\frac{x^2-81}{x^2-9}\\
=\frac{2x(x-3)}{(x+9)^2}\times\frac{(x+9)(x-9)}{(x+3)(x-3)}\]

Answer 4

Which answer is that going to turn out to be?

Answer 5

cancel out what is common in the numerator and denominator..
Notice that:
\[ \frac{2x(x-3)}{(x+9)^2}\times\frac{(x+9)(x-9)}{(x+3)(x-3)}=\frac{2x(x-3)(x+9)(x-9)}{(x+9)(x+9)(x+3)(x-3)}\]

Answer 6

Ahhhh... Let me go try to simplify that and I'll brb

Answer 7

I got C, @kirbykirby ... Thank you so much for your help!

Answer 8

yup :)

Answer 9

yeah, that was just a lot of factoring practice ....