No one has been able to help! Please help I'll give a medal! Simplify the rational expression
x^2+2x-35/x^2+4x-21
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OpenStudy (anonymous):
@jim_thompson5910 do you mind helping me please?!
jimthompson5910 (jim_thompson5910):
Are you able to factor any of the expressions?
OpenStudy (anonymous):
The answer I got was x+5/x+3 but idk if that is right
jimthompson5910 (jim_thompson5910):
what do you get when you factor the numerator?
OpenStudy (anonymous):
I got x^2+2x-35=(x+7)(x-5)
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jimthompson5910 (jim_thompson5910):
how about the denominator
OpenStudy (anonymous):
(x-7)(x+3)
jimthompson5910 (jim_thompson5910):
that's incorrect
jimthompson5910 (jim_thompson5910):
notice how -7+3 = -4 but we want +4 instead
OpenStudy (anonymous):
Oh ok! so what do I do next
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jimthompson5910 (jim_thompson5910):
what's the correct factorization of the denominator?
OpenStudy (anonymous):
7-3=4 so (x+7)(x-3)?
jimthompson5910 (jim_thompson5910):
So we will get this:
\[\Large \frac{x^2+2x-35}{x^2+4x-21}\]
\[\Large \frac{(x+7)(x-5)}{x^2+4x-21}\]
\[\Large \frac{(x+7)(x-5)}{(x+7)(x-3)}\]
\[\Large \frac{\cancel{(x+7)}(x-5)}{\cancel{(x+7)}(x-3)}\]
\[\Large \frac{x-5}{x-3}\]