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OpenStudy (pinksapphire):
What would be the answer for this expression?
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OpenStudy (pinksapphire):
\[\sqrt{20}+\sqrt{8}-\sqrt{80}\]
zepdrix (zepdrix):
\[\Large\rm \sqrt{20}=\sqrt{4\cdot5}\]Hmm does sqrt(2) contain any perfect squares?
Anything we can take out of the root?
OpenStudy (pinksapphire):
\[\sqrt{4}=2\]
zepdrix (zepdrix):
\[\Large\rm \sqrt{20}=2\sqrt{5}\]Mmm ok great! that allows us to take the 4 out of the root as a 2.
zepdrix (zepdrix):
How bout the 8? :U
Any magic we can do there?\[\Large\rm \sqrt{8}=\sqrt{4\cdot2}\]
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OpenStudy (pinksapphire):
\[\sqrt{4\times2} \]
OpenStudy (pinksapphire):
Sorry, my internet is kind of bad today :(
OpenStudy (pinksapphire):
@zepdrix?
zepdrix (zepdrix):
It's probably not your internet :c it's the website...
zepdrix (zepdrix):
Can we take a perfect square out of the 8?
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OpenStudy (acxbox22):
once you have a common number under the radical you can add and subtract the numbers outside the radical
for example 3sqrt5-sqrt5=2sqrt5
OpenStudy (pinksapphire):
No, we can't have a perfect square root of 8.
OpenStudy (acxbox22):
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