Question

How to calculate average velocity of a particle if , its position is given

Answer 1

position ?
plz privide an example if psple :D

Answer 2

Position - x= a+bt^2
a= 8.5 m
b= 2.5 m

What is the average velocity between t=2.0 s and t= 4.0 s



Do we have to calculate inst velocity here for average?

Answer 3

well no , just fint
x(2.0 ) and x(4,0 )
add then devide 2 which is the avg
thats what im think off :O
but im not sure , im very sleepy

Answer 4

Yes , 4x and 2x like how
Can u elaborate

Answer 5

I won't take time

Answer 6

x= a+bt^2
well its like x= f(t )

Answer 7

So at 2

F(2) = a+4b ?

Answer 8

yep

Answer 9

So

[a+16b - a- 4b]/2

6*b= 6*2.5 = 15m/s

And that is the answer , yes , thank youu!

Answer 10

:) np

Answer 11

waitttt ... im wrong

Answer 12

You are not

Answer 13

The textbook says so , lol

Answer 14

f(t) = a+bt^2 it tells u the position
f(t)' =2bt gives u the velocity

Answer 15

well the tt book have the whol answer all only the avg ?

Answer 16

2bt is the instantaneous velocity not average

Answer 17

I didn't get what you were saying?

well the tt book have the whol answer all only the avg ?

Answer 18

waittt ok ok
then
\(\large avg = \Huge \frac{f(t_1)+f(t_2)} {t_1 - t_2}\)
ok nw its better :)

Answer 19

im a bit sleepy lol so making typo's
forgive meee :D

Answer 20

No problem :)

Answer 21

f(t1) - f(t2) IT IS NOT PLUS

Answer 22

okk

Answer 23

ok