Ask your own question, for FREE!
Mathematics 54 Online
OpenStudy (mikezack123):

please help

OpenStudy (mikezack123):

OpenStudy (mikezack123):

@Abhisar @dan815 @Hero

OpenStudy (mikezack123):

YAY @satellite73 IS HERE

OpenStudy (anonymous):

guess we have to solve it

OpenStudy (mikezack123):

can you please show me the steps i don't even know where to start.. :/

OpenStudy (anonymous):

\[-3\leq -2x+1<11\] subtract \(1\) get \[-4\leq -2x<10\]divide by \(-2\) and change the inequalities

OpenStudy (mikezack123):

what do i divide by 2?

OpenStudy (anonymous):

you get \[2\geq x>-5\] or if you prefer \[-5<x\leq 2\]

OpenStudy (anonymous):

you divide nothing by \(2\)

OpenStudy (mikezack123):

oh all the sides of the equation by -2 right? lol sort forgot the negative

OpenStudy (anonymous):

at this step \[-4\leq -2x<10\] the coefficient of the \(x\) term is \(-2\) not \(2\) so you have to divide all by \(-2\) to get \(x\) by itself in the middle

OpenStudy (anonymous):

a

OpenStudy (mikezack123):

oh okay thank you it should be either a or c but how do i know if its a open or closed circle?

OpenStudy (mikezack123):

i forgot that :/

OpenStudy (mikezack123):

@satellite73 ?

OpenStudy (anonymous):

that is easy enough

OpenStudy (anonymous):

\[<\] or \[>\] OPEN

OpenStudy (anonymous):

\[\leq\] or \[\geq\] CLOSED

OpenStudy (anonymous):

answer: a

OpenStudy (anonymous):

look for the presence of absence of the line underneath

OpenStudy (mikezack123):

so its line A correct?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

yes

OpenStudy (mikezack123):

Thank you @satellite73 !!!!

OpenStudy (anonymous):

yw

OpenStudy (mikezack123):

thanks! @cgoel

OpenStudy (anonymous):

yup

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!