How do I factor (1x-4)(x-2) completely? Please explain! Will become a fan of the first person who replies.
Ummm... \((1x-4)(x-2)\). That is factored.
looks factored to me
but maybe there is a typo, because one usually does not write \[1x\]
1x = x
Can you make sure of how it is supposed to look? Use ^ for any powers, or use the equation editor.
Maybe by factor completely, she means "expand" completely.
If u want to exppand , Use the door-keeper method of wxpansion
Wouldn't you have to set it equal to zero?
You talking about quadratic equation
No, that would be to find the zeros. Factoring is just putting it into multiplicative form. Let me see if I can find a good definition of factoring.
I am not just getting what you want to say, you first post factor, then you are saying about expansion , Then you say about setting it to zero I am confused could you please clarify the textbook question
"Finding what to multiply to get an expression. (Called Factorizing in British English.)" http://www.mathsisfun.com/definitions/factoring.html
Anyways...apparently the correct answer is (3x - 2)(x + 4). The original problem is 3x^2+10x-8 in case any of you were wondering.
clarify the question
Ah, so you made a mistake in factoring. Always good to show the original and ask if your answer is correct.
@No.name This is the question- Which is the complete factorization of the trinomial 3x2 + 10x - 8?
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