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Mathematics 14 Online
OpenStudy (anonymous):

I think i know the answer, can you help me? If AR = 12 m and AE = 16 m, what is the ratio of the area of ARH to the total area of AES?

OpenStudy (anonymous):

I think it it 9/16

OpenStudy (anonymous):

Options are 3/4, 4/9,9/16, and 9

OpenStudy (nikato):

do you have a picture to go with it?

OpenStudy (anonymous):

I think so one moment

OpenStudy (anonymous):

OpenStudy (anonymous):

Hello again!

OpenStudy (anonymous):

My guess answer is 3/4, but i think its 9/16

OpenStudy (anonymous):

So yeah...

OpenStudy (anonymous):

Do do do...

OpenStudy (anonymous):

Your picture is so cute! ITS SO FLUFFY!

OpenStudy (anonymous):

I got medal :D from you!

OpenStudy (nikato):

yea. i think its 9/16 3/4 is the ratio of the sides of the triangles. the ratio of the area would be the square of that which is 9/16

OpenStudy (anonymous):

Yeah i gave you best response!

OpenStudy (anonymous):

Alright thanks so much, BTW i am kinda new so if i need help again i can post another question

OpenStudy (anonymous):

Alright thanks again!

OpenStudy (nikato):

ok. no problem. glad to help you

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