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Mathematics 9 Online
mathslover (mathslover):

Continuity Question Let : \(\large{ f(x) = \left\{\begin{matrix} (1+|\sin x|)^{a/|\sin x|} , & -\pi/6 < x < 0 \\ b, & 0\\ e^{\tan 2x / \tan 3x } , & 0 < x < \pi / 6 \end{matrix}\right. }\) Determine a and b such that f is continuous at x = 0.

mathslover (mathslover):

@ganeshie8

mathslover (mathslover):

@Miracrown

OpenStudy (nipunmalhotra93):

Lim x->0 \[Lim _{x->0}(1+|Sinx|)^{1/|Sinx|}=e\](1+|sinx|)^(1/|sinx|)

OpenStudy (nipunmalhotra93):

^this will help.. ignore what's written at the end

OpenStudy (anonymous):

a = 2/3 b = e^(2/3) I cheated, don't ask me how XD

mathslover (mathslover):

Wait, I will be back.... have to go for breakfast... Sorry :(

OpenStudy (anonymous):

Quick question, you just started calc and they gave you this? Or do you like to just make it difficult for us XD

OpenStudy (nipunmalhotra93):

@mathslover use sint/t->1 as t->0 to determine the limit of e^(tan2x/tan3x) as x->0

mathslover (mathslover):

;p; @iambatman I had completed Differentiation and Application of Derivatives just today... and I have been doing problems on Limits, Continuity and Differentiation...! So, this is one of the problems I was doing

mathslover (mathslover):

@nipunmalhotra93 I think e is not correct... will it be e^a ?

mathslover (mathslover):

Oh yes.. you have taken 1 in numerator... and it is a in numerator so, it will be e^a

OpenStudy (nipunmalhotra93):

yeah

mathslover (mathslover):

But, I didn't get the 2nd part...

mathslover (mathslover):

Okay, I got it.

mathslover (mathslover):

\(e^{\cfrac{\tan 2x}{2x} \times \cfrac{3x}{\tan 3x} \times \cfrac{2}{3} }\) = \(e^{\cfrac{2}{3}}\) = b and a = 2/3........

mathslover (mathslover):

Thank you @nipunmalhotra93

OpenStudy (nipunmalhotra93):

np :)

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