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Mathematics 14 Online
OpenStudy (anonymous):

(√7+√x) /(√7-√x)

OpenStudy (anonymous):

by the slash, is that supposed to be your division sign?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Do you mean?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

can you help me with it? @FDV

OpenStudy (anonymous):

Yes, hold on.

OpenStudy (anonymous):

What way way do you need it as? (plot, alternate form, expanded form, etc.

OpenStudy (anonymous):

i just need to simplify it

OpenStudy (anonymous):

Okay, here.

OpenStudy (anonymous):

If that wasn't what you were looking for: search for wolfram alpha on google then search for type "(√7+√x) /(√7-√x)" simplified it gives answer + explanation

OpenStudy (unklerhaukus):

\[\frac{√7+√x}{√7-√x}\] \[=\frac{√7+√x}{√7-√x}\times1\] rationalise the denominator , by multiplying by it's irrational conjugate ( the irrational conjugate of \(\sqrt 7-\sqrt x\) is \(\sqrt 7+\sqrt x\) ) \[=\frac{√7+√x}{√7-√x}\times\frac{\sqrt 7+\sqrt x}{\sqrt 7+\sqrt x}\]

OpenStudy (unklerhaukus):

\[=\frac{(√7+√x)(\sqrt 7+\sqrt x))}{(√7-√x)(\sqrt 7+\sqrt x)}\] the denominator simplifies to become a rational \[=\frac{(√7+√x)(\sqrt 7+\sqrt x))}{7-x}\] and the numerator simplifies \[=\frac{(√7+√x)^2}{7-x}\]

OpenStudy (unklerhaukus):

understand? @cutegirl

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