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OpenStudy (anonymous):
by the slash, is that supposed to be your division sign?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
Do you mean?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
can you help me with it?
@FDV
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OpenStudy (anonymous):
Yes, hold on.
OpenStudy (anonymous):
What way way do you need it as? (plot, alternate form, expanded form, etc.
OpenStudy (anonymous):
i just need to simplify it
OpenStudy (anonymous):
Okay, here.
OpenStudy (anonymous):
If that wasn't what you were looking for:
search for wolfram alpha on google
then search for type "(√7+√x) /(√7-√x)" simplified
it gives answer + explanation
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OpenStudy (unklerhaukus):
\[\frac{√7+√x}{√7-√x}\]
\[=\frac{√7+√x}{√7-√x}\times1\]
rationalise the denominator , by multiplying by it's irrational conjugate
( the irrational conjugate of \(\sqrt 7-\sqrt x\) is \(\sqrt 7+\sqrt x\) )
\[=\frac{√7+√x}{√7-√x}\times\frac{\sqrt 7+\sqrt x}{\sqrt 7+\sqrt x}\]
OpenStudy (unklerhaukus):
\[=\frac{(√7+√x)(\sqrt 7+\sqrt x))}{(√7-√x)(\sqrt 7+\sqrt x)}\]
the denominator simplifies to become a rational
\[=\frac{(√7+√x)(\sqrt 7+\sqrt x))}{7-x}\]
and the numerator simplifies
\[=\frac{(√7+√x)^2}{7-x}\]