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The length in cm of components manufactured by a machine come from a normal population with mean 36 standard deviation 2.5. if 5 components are randomly selected from the machine's output. What is the probability at least 2 are are longer than 37.5cm
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I found it , if anyone is interested P(X > 37.5) = P((X-35)/2.5 > (37.5-35)/2.5) = P(Z > 1) . Get P(Z > 1) off standard normal table by 1-P(Z<1)=
1-0.8413=0.1587
Now using the binomial with P(Y>=2)=1-P(Y<2) n=5 and p=P(Z>1)=0.1587
final answer is 0.1810 , correct me if i am wrong
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