MEDAL AND FOLLOW
Shelly delivers the weekly local paper to neighborhoods in her town. House numbers are even on one side of the street and odd on the other. Shelly delivers an equal number of papers to both sides of the street. Although she always aims for the front doorstep, Shelly typically misses on three of the tosses on her route each week. Design and conduct a simulation to estimate the probability that next week, Shelly's three misses will all be at odd-numbered houses. Hint: You can set up the experiment using 3 coins to collect the data. Allow one side of the coin to represent Heads (evens) and one other side to represent Tails (odds). a) Explain clearly your design of the simulation, including choice of probability tool and description of a single trial. b) Conduct the simulation with twenty trials and record the results. c) Calculate the experimental probability that all 3 of Shelly's missed papers will be at odd-numbered houses
@phi
@faylynn
the answers c!!
yup got to be c!
but none of those are answers
ab or c
hmmmm
hmmm
what??
oh... i see... wow.. u have to do all that??
i just dont undeerstand @phi
Its basically just fractions times each other 1/2 x 1/2 x 1/2 = 1/8 Its 1 eighth probability So 0.125 Or 12.5% Or 1/8
do ya get it?
yeah.. that right listen to that person!! @kitetenjo
kinda like umm
ohhh i get it like 12.5 % is part of the answer?
pretty much. all it is just fractions times each other.
so the bottom part would be the answer? like the fractions and and percent?
@kitetenjo
6 houses on the street 3 on each side
On second though, I am making it too hard. Let's just say there are 3 misses.
toss a coin if you get tails, that means the first miss was on the odd side if you get heads, that means the first miss was on the even side
ok then what
then do that experiment again for the second miss and finally a third time for the third miss write down the results. that will be the first trial you have to do that 20 times
aghh this is so confusing
the answer to part (a) a) Explain clearly your design of the simulation, including choice of probability tool and description of a single trial. is there are 3 misses. we will simulate whether a miss is on the odd or even side by flipping a coin Heads (even side) and Tails (odd side). we will toss the coin 3 times to find which side the first, second and third miss happen
ohhhh
and how many times do i have to do it?
oh 20
part (a) explains how to do "one trial" part (b) says do 20 trials (which means 3*20 or 60 flips of the coin total) and record the results part c says count the number of trials where you got 3 tails the probability will be that number divided by the total number of trials i.e. divided by 20
i have to flipa coin 60 times 0_o
flipping a coin (unless it rolls under the couch) is not hard.
can u just help me with this one plz @phi
Brenda is training to be a volunteer at her library. She wonders what the probability is that the first item she'll get to check out for a customer will be a video. So, on her first day of training, she tracks what items are checked out. The results are shown here in a tally chart. Brenda wrote tally marks for what type of item various customers check out. For books, there are seven groups of 5 tally marks and two individual marks. For videos, there are four groups of 5 tally marks and four individual marks. For magazines, there are three groups of 5 tally marks and four individual marks. Use Brenda's experimental data to estimate the probability that her first item to check out will be a video. Show and explain your work.
add up how many books, videos and magazines were checked out. example: books, seven groups of 5 tally marks and two individual marks. means 7 * 5 + 2 = 35+2 or 37 books. do that for videos and mags add up all 3 numbers to get a total number then make a fraction: number of videos divided by total number that will be the probability of picking a video
oh ok thanks
post your answers, and someone will check that you did it correctly
books, 37 books videos, 24 videos magazines, 19 all together = 80 what should i do next @phi
make a fraction: number of videos divided by total number that will be the probability of picking a video
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