Question

How do I solve a problem with 3 radicals.

Answer 1

\[\sqrt{x+\sqrt{2x}} = \sqrt{2x}\]

Answer 2

start by squaring both sides

Answer 3

\[(\sqrt{x+\sqrt{2x}})^{2} = (\sqrt{2x})^{2}\] like this?

Answer 4

yes cancel the radical

Answer 5

\[x+\sqrt{2x} = 2x\] Now what do I do?

Answer 6

subtract x both sides

Answer 7

Would it be\[\sqrt{2x} = 2x-x\]

Answer 8

To give me \[\sqrt{2x} = x\]

Answer 9

yes !

square it again

Answer 10

Then I would have,\[2x = x^{2}\] is this true?

Answer 11

Correct !

Answer 12

its a quadratic,
u can factor it and solve x