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OpenStudy (anonymous):
Please help!
4cos (theta) + 1= 2cos (theta)
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OpenStudy (anonymous):
@jim_thompson5910
OpenStudy (anonymous):
@robtobey
hero (hero):
\(4\cos(\theta) + 1 = 2\cos(\theta)\) right?
OpenStudy (anonymous):
yes!
hero (hero):
For the moment, let \(x = \cos(\theta)\)
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hero (hero):
Now you have \(4x + 1 = 2x\)
hero (hero):
Solve for x
OpenStudy (anonymous):
2x=-1?
hero (hero):
To finish solving for x, divide both sides by 2 right?
OpenStudy (anonymous):
ohh, yes!
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OpenStudy (anonymous):
you would get x= -1/2
hero (hero):
Also, I'm going to have to ask you to change your username to something with a more positive connotation.
OpenStudy (anonymous):
lol, will do
hero (hero):
Which means
\(\cos(\theta) = -\dfrac{1}{2}\)
hero (hero):
Now take inverse cosine of both sides to isolate \(\theta\)
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OpenStudy (anonymous):
so the inverse cosine would be 120 degrees?
OpenStudy (anonymous):
and 240 degrees
OpenStudy (anonymous):
which would be 2pi/3 and 4pi/3?
hero (hero):
2pi/3 is correct
hero (hero):
From where did you get 4pi/3 ?
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OpenStudy (anonymous):
from 240 degrees
OpenStudy (anonymous):
i was suppose to find 0< theta< 2pi. that means the whole unit circle right? I forgot to write that in the original question D:
OpenStudy (anonymous):
thank you so much
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