Please help! 4cos (theta) + 1= 2cos (theta)
@jim_thompson5910
@robtobey
\(4\cos(\theta) + 1 = 2\cos(\theta)\) right?
yes!
For the moment, let \(x = \cos(\theta)\)
Now you have \(4x + 1 = 2x\)
Solve for x
2x=-1?
To finish solving for x, divide both sides by 2 right?
ohh, yes!
you would get x= -1/2
Also, I'm going to have to ask you to change your username to something with a more positive connotation.
lol, will do
Which means \(\cos(\theta) = -\dfrac{1}{2}\)
Now take inverse cosine of both sides to isolate \(\theta\)
so the inverse cosine would be 120 degrees?
and 240 degrees
which would be 2pi/3 and 4pi/3?
2pi/3 is correct
From where did you get 4pi/3 ?
from 240 degrees
i was suppose to find 0< theta< 2pi. that means the whole unit circle right? I forgot to write that in the original question D:
http://www.wolframalpha.com/input/?i=inverse+cosine+%28-1%2F2%29%2C+0+%3C+theta+%3C+2pi
thank you so much
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