would either of you b able to help me with these @Juicstice @dan815
I got you on the first one. so what you do is with the big triangle do pythagorean theorem to fin the longest side then just subtract 6
but I'm still missing a side in addition to x....so wouldnt i b finding 2 variables then?
whoops do what I told you but with the smaller triangle then to find the other missing side you have to set up an equation that would look like this A^2+B^2=(x-6)^2
ok so would it look like this? 10^2 = 6^2 + b^2' 100 = 36 = b^2 64 = b^2 b = 8
then for ....ummm... idk what to do after taht
*that
yes, then just put 8 into the equation I wrote down and solve for (hint: it will have an x in it just imagine that you are simplifying the equation)
solve for A
*
ok I thnk I see what ur saying...let me do it on paper...then I'll type it
okay I hope I'm helping
your getting me farther than i coud:)
*could
\[A^2 + B^2 = (x-6)^2 \] \[A^2 + 8^2 = (x-6)^2\] \[A^2 + 84 = (x-6)^2\]
this is as far as I've gotten?....do I add 6?
first you square the numbers in the parenthesis
so x^2 + 36?
ok so after that...subtract 36 from each side?
yes
more like you should subtract 84 from 36
it should actually b 64...i wrote that wrong sorry... 8^2 = 64
A^2 + 28 = x^2 ??
okay, I should have seen that, that's my fault
no biggie I knew it was 64...just a type....but is that equation above right?
*typo
okay so I might have messed something up with just the placement of the equation it should look like 8^2+(x-6)^2=C^2 and to solve for (x-6)^2 you have to foil, I know that sucks but it has to be done that should make more sense
haha u read my mind about that part sucking....ok so it would look like 28 + x^2 = C^2..... i dont think i did that right at all....did I even foil??
thats how much i hate foiling i forgot from when they taught me last year how to do it! :p
no you didn't |dw:1401917781975:dw|
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