Question

Find the slope of the line tangent to the line graph of the equation

y=(2x^2+3)(x-1) at x=2

help on how to solve please? <3

Answer 1

take the derivative
replace \(x\) by \(2\)

Answer 2

Expand (2x^2 + 3)(x - 1) first before taking the derivative.

Answer 3

@satellite73 should I factor the two together first then find the derivative?

Answer 4

@Hero do you mean factoring them together first?

Answer 5

@Isabellaxoxo, if you expanded first, the result will still be equal to what you had before.

Answer 6

Expand means multiply it out

Answer 7

@Hero Right. Then once thats done I just sub the 2 in for x?

Answer 8

No, you still have to take the derivative before doing that.

Answer 9

@Hero Ohhh I got cha! Thank you!!!

Answer 10

Did you expand (2x^2 + 3)(x - 1) already?

Answer 11

@Hero just about to do that now :)

Answer 12

Show your work

Answer 13

ok so my work was:

(2x^3+3)(x-1)

2x^3-2x^2+3x-3

(3)(2)x^(3-1) - (2)(2)x^(2-1) + (1)(3)x^(1-1) - (0)(3)

6x^2-4x+3

Answer 14

@Hero

Answer 15

(2x^3 + 3)(x - 1) = 2x^3(x - 1) + 3(x - 1)
= 2x^4 - 2x^3 + 3x - 3

Answer 16

Oh gosh sorry I meant to put (2x^2+3) not (2x^3+3) Thank you so much @Hero for helping me so much!! <3