Find the pH and pOH of 10^-2 M of HCI
I really need help with this question, I have an exam tomorrow morning and this is on the review and I have no idea how to solve it.
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Since HCL is a strong acid, it completely ionizes. Thus 10^-2 M of HCL will give the same amount of H+ ions
can you help me? @Abhisar
Now pH = -log(H+)
Okay so pH= -log(10^-2)= 2
So the pH of HCL will be \[-\log \left( 10^{-2} \right)\]
yes u got it
and then from there I just do 14-2 right? to find the pOH?
yes pH + pOH = 14
Thank you so so much!
\(\Huge\text{Anytime !}\) \(\huge\ddot\smile\)
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