Question

calc help

Answer 1

btw this isn't really calc, but no matter, we can do it anyways

Answer 2

oh now it is !

Answer 3

the solution to the first one is
\[y=c_1e^{-2t}+200\]

Answer 4

with initial condition \(y(0)=100\) you get
\[y=200-100e^{-2t}\]

Answer 5

so not that one

Answer 6

we can do the next one quickly i think

Answer 7

ok

Answer 8

or just go right to the answer
\[y'=2(y-200),y(0)=50\] gives
\[y=-150e^{2t}+200\]

Answer 9

as \(t\to \infty\) you have \(-150e^{2t}\to -\infty\)

Answer 10

i didn't check the others, just guessed at that one
should we check them?

Answer 11

yah sure

Answer 12

ok it is not the last one, because that gives
\[y=150e^{2t}-200\] and that does not go to \(-\infty\)

Answer 13

u get my message?

Answer 14

no need to check the rest i think
for the correct one,
\[y'=2(y-200)\] you have the right combination of \(+2\) and \(-200\)

Answer 15

thnxs and u get my message?

Answer 16

yeah, just responded

Answer 17

go ahead and post the next one

Answer 18

These are all of them

Answer 19

whoa ok one at a time
lets do the first one first

Answer 20

ok lol

Answer 21

first one
second derivative is negative for \(x>2\)

Answer 22

ok thnxs

Answer 23

u r life saver

Answer 24

second one
the second derivative is zero at \(x=2\)

Answer 25

take your time

Answer 26

third one
the derivative is \( -(1-2 x)^2 (8 x-1)\) at \(x=1\) you get \(-7\) as the slope
only one choice there

Answer 27

pick A

Answer 28

ok awsome thankyou!, could u number them like 1. 2. and son so I dont get mixed up either lol thnxs

Answer 29

*so typo

Answer 30

ok that was #3

Answer 31

#4 first derivative is \(2\tan(x)\) and \(\frac{\pi}{4}\) you get \(2\)so the slope of the normal line is \(-\frac{1}{2}\)

Answer 32

ok cool

Answer 33

thnxs

Answer 34

wait wait that was #6

Answer 35

i don't see #4 and #5

Answer 36

they r out of order

Answer 37

just write the number in the screenshot because all of the other s I solved by myself

Answer 38

#7 the derivative of \(\frac{\ln(x)}{x}\) is
\[\frac{1-\ln(x)}{x^2}\]

Answer 39

i will just keep numbering them

Answer 40

just sent you a message

Answer 41

k

Answer 42

Woahh... big medal for @satellite73

Answer 43

yah