Murat has a lock for his locker that has a 4-digit combination. Each digit can range from 1 to 5. If each digit of the combination must be different, how many possible combinations are there?
A.4 × 3 × 2 × 1

B.5 × 4 × 3 × 2

C.5 × 5 × 5 × 5

D.5 × 4 × 4 × 4

Question

Murat has a lock for his locker that has a 4-digit combination. Each digit can range from 1 to 5. If each digit of the combination must be different, how many possible combinations are there?
A.4 × 3 × 2 × 1

B.5 × 4 × 3 × 2

C.5 × 5 × 5 × 5

D.5 × 4 × 4 × 4

paki · Answer

have you any idea of the term "COMBINATION"....?

anonymous · Answer

yeah i dont remember how to do theese. :(

shamim · Answer

we can fill up by 5 ways for first disit

paki · Answer

hm... what if i say "5!"...?

paki · Answer

5!..... !=factorial sign....

anonymous · Answer

ok.....

shamim · Answer

we can fill up by 5 ways second disit

shamim · Answer

third nd fourth disit r also fill up by 5 ways

paki · Answer

factorial can be solved like by this... 5*4*3*2*1.... ok

anonymous · Answer

ok.

shamim · Answer

result will b 5*5*5*5

anonymous · Answer

hmmmm.... ok i think i know what to do. thank you!

paki · Answer

no... it will be 5*4*3*2*1 ...

@shamim  in question it is " combination must be different ".... so this will be the procedure...

shamim · Answer

5555 may b a lock?

paki · Answer

@tiwall have a look here for detail.... http://www.mathsisfun.com/numbers/factorial.html

anonymous · Answer

ok, thank you!!!! :)

paki · Answer

pleasure...