Modulus and log
\[\huge \left| x-3 \right|^{3x^2-10x+3}=1\]
Tried taking log both sides?
right hand sde would become 0
\(3x^2 - 10x + 3 \log |x-3| = 0\)
Yeah, RHS will become 0. Using power rule, the power of |x-3| will come out of the log as multiplication. \((3x^2 - 10x + 3) \log |x-3| = 0\)
So, you have two cases \[ \left\{ \begin{array}{lr} 3x^2 - 10x + 3 = 0\\ \log |x-3| = 0 \end{array} \right. \]
the first one can be solved
\(\cfrac{10 \pm \sqrt{100 - 36}}{6} = \cfrac{10 \pm 8 }{6} = 3 ~~ \text{or} ~~\cfrac{1}{3} \) So, x = 3 or 1/3 for the given function to be zero. Now, for \(\log |x-3| = 0 \) There are again two cases.
how does log of moduluses work
Squaring both sides will work I think.
No. that will not work.
1st case :- log(x-3) =0 x-3=1 x=4 2nd case -log(x-3)=0 dividing by -1 log(x-3)=0 x-3=1 x=4
b^(x-3)=3n for any b>1
When x is real then \(\log |x-3| = \cfrac{1}{2} \log (x-3)^2 = 0 \) Thus, \(\log (x-3)^2 = 0\)
What's wrong with the above method
As \(\log (x-3)^2 = 0\) Therefore, \( (x-3)^2 = 1\) Thus, x-3 = 1 or x-3 = -1 x = 4 or x = 2
Why did you square , and what's wrong with the method i did
The method I did followed the properties of logarithms. You can follow this method - log|x-3| = 0 |x-3| = 1 (x-3) = - 1 or (x-3) = 1 x = 2 and x = 4 For your method (x-3) = +1 or (x-3) = -1
\(\color{blue}{\text{Originally Posted by}}\) @No.name 2nd case -log(x-3)=0 dividing by -1 log(x-3)=0 \(\bf{x-3=1} \) x=4 \(\color{blue}{\text{End of Quote}}\) The bolded text has the problem... you only took one condition which is x-3 can also be equal to (-1)
3 won't be the solution
* which is x-3 = 1 but (x-3) can also be equal to -1
Yeah i did some goof up there but you got the point. I am already a bit frustated as my internet is not working
That's modern generation... ^ We all are depended on internet.... ! When it doesn't work, we get frustrated hahahah ... ! Have fun.
make sure to check all the solution you get, by plugging them into original equation, and checking whether left side = right side. you will find that x= 3 is not a solution
I wonder how my parents did engineering without internet yes @hartnn
Oh yes.. 3 wouldn't be a soln @hartnn - you got a point.. gr8
If there was no google / wiki -> all would have been playing out door games and having fun with friends RATHER THAN playing video games ... all would have been going to their friends/teachers to ask questions RATHER THAN openstudy..
* no internet (not google/wiki :P )
wiki is not reliable!!!
Its not a reliable source, anyone can edit on it... so when looking for info you've always gotta look at other resources to ensure the info is valid.
Nothing is reliable then...! What say?
Animals are reliable, many full of love, true in their affections, predictable in their actions, grateful and loyal. Difficult standards for people to live up to. =)
if only animals can solve math :P
lol
Humans are also animals... lol! WILD ANIMALS (btw, this is getting off-topic, lets discuss it in chats)
No, last time I saw a lion solving Integral problem @hartnn ... he was almost there, hitting his heads hard at the ground ...
We have no reliable guarantee that the afterlife will be any less exasperating than this one, have we?
I once caught 2 stray kittens and tied rope around each one and gave one to my brother and we had kitten fights
Animals can't solve modulus and logarithms
You all are newbs.\[a^b = 1\]means\[a = 1\]and for all other cases\[b = 0\]
yessss elephants are one of the most intelligent animals around! :P
So \(|x - 3| =1\) and for all other cases, \(3x^2 - 10x + 3 = 0\). No goofing up.
parth, we got same thing by solving
yeah just look at ganeshie8
Kewl.
Why log though?
because steps carry marks
LOL
Finally, my BSNL net worked ahaha
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