How do I find the P-value?: H0: the true proportion of females is equal to 60%. Two-sided. results were statistically significant at 10%, but not at 1%....?

Question

anonymous · Answer

That depends on the test you're using, but judging by the null hypothesis' phrasing, you're testing for the proportion. So, you'll be using a Z test statistic:
$$Z=\frac{\hat{p}-p_0}{\sqrt{\dfrac{p_0(1-p_0)}{n}}}$$
where $H_0:~p_0=0.6$, $\hat{p}$ is the estimated proportion, and $n$ is the sample size.

It looks like you're saying for an $\alpha=0.1$ significance level, the null hypothesis is rejected, but not for an $\alpha=0.01$ significance level.

For the first condition to be met, the calculated $Z$ must satisfy $|Z|>1.645$, and for the second, $|Z|<2.57$.

To summarize, you have $1.645<|Z|<2.57$.

The p value depends on exactly what $Z$ you calculate.