Question

parametric equation of a line through 2 points. I know the equation is r(t) = + t, but it doesn't seem to scale

Answer 1

so i have 2 points:
initial = <0, -.5, 0>
terminal = <.1, -.5, 0>

Answer 2

if you set t = 2, the point isn't on the same line right?

Answer 3

get the direction vector by subtracting both the corrdinates

Answer 4

basically i'm creating a 3d program and i need to translate a distance (i guess being the parameter t) and plot it on the same line

Answer 5

direction vector = <.1, -.5, 0> - <0, -.5, 0>
= ?

Answer 6

hrm what do you do with the direction vector tho?

Answer 7

oh i see so if you get the direction vector then you can just scale based on that

Answer 8

so it would be <.1, 0, 0>

then if you wanted a distance of say 2, you just do 2 dot <.1, 0, 0>

Answer 9

but then how do you plot that on the same line?

Answer 10

line passing thru below two points :
initial = <0, -.5, 0>
terminal = <.1, -.5, 0>

is r = <0, -.5, 0> + t<.1, 0, 0>

Answer 11

<,1, 0, 1> gives the direction, and the fixed point gives the location

Answer 12

you will get the terminal point, when \(t = 1\) ^

Answer 13

im not so sure ive answered ur question lol

Answer 14

erm not sure if it works out tho. here's an example
initial = <0, -.5, 0>
terminal = <.1, -.5, 0>
r(t) = <.1T, -.5 - .5T, 0>, which comes from <0, -.5, 0> + T<.1, -.5, 0>

then if say you wanted something past the terminal point, say a distance of 2

T = 2, so <.2, -1.5, 0> would be the answer, but this isn't on the same line

Answer 15

the answer should be <.2, -.5, 0>

Answer 16

direction vector doesn't look right

Answer 17

initial = <0, -.5, 0>
terminal = <.1, -.5, 0>

direction vector = <.1, 0, 0>

equation of line is : r(t) = <0, -.5, 0> + t <.1, 0, 0>

Answer 18

plugin t = 2

Answer 19

ohhhhhhhhh so you use the direction vector as the terminal point

Answer 20

as the name says, direction vector just tells about the direction...
in some sense, its like `m` in the 2d equaiton `y = mx+b`

Answer 21

ah ok that makes sense. thank you so much

Answer 22

np :)

Answer 23

good luck wid the program !!