Question

Solve for the roots in the equation below.
x^4 + 3x^2 - 4 = 0

Answer 1

x=2i,-2i,1,-1

Answer 2

Can you show how you got x=2i,-2i,1,-1? @GotToLoveJenny

Answer 3

(x^2 +4 ) *(x^2 -1 ) =0

x^2 -1 =0
(x-1)(x+1)=0
x-1=0 so x=1
x+1=0 so x=-1

x^2 +4=0
x^2=-4
\[x=\sqrt{-4}\] it is not found as real

but as imaginary x=+2i ,x=-2i
as i=\[\sqrt{-1}\]

Answer 4

\[\sqrt{-4}=\sqrt{4}*\sqrt{-1}=2*\sqrt{-1}\]

Answer 5

thanks hanishala

Answer 6

you are welcome @GotToLoveJenny

Answer 7

so the roots are?

Answer 8

2i ,-2i ,1 ,-1

Answer 9

the roots are sqrt-4,+2i,-2i, sqrt-1?

Answer 10

or 2i, -2i, 1, -1?

Answer 11

2i ,-2i ,-1 ,1 @Power2Knowledge

Answer 12

Thank you, my pc had glitched.