Question

Help Please

Factor completely: 16x4 – 1









A.

(2x + 1)^3(2x – 1)








B.

(4x^2 + 1)(2x + 1)(2x – 1)








C.

(4x + 1)(4x – 1)








D.

(4x^2 + 1)(4x^2 – 1)

Answer 1

16x^4-1

Answer 2

u need that factored also

Answer 3

(2x+1)^3(2x-1)
Polynomial not factorable

Answer 4

That's the original one, I just corrected it

Answer 5

B. (4x^2+1) (2x+1) (2x-1)
Answer: Not factorable

C. (4x+1) (4x-1)
Answer: Not Factorable

D. (4x^2+1) (4x^2-1)
Answer: (4x^2+1)(2x+1)(2x-1)

Answer 6

To get the answer you're supposed to factor 16x^4-1, not factor the answer choices.

Answer 7

oh lol im very sorry

Answer 8

let me do that

Answer 9

anyways the answer is D.

Answer 10

Thanks for the medal

Answer 11

No problem

Answer 12

@aajugdar

Answer 13

you can write this equation as
\[((4x^2)^2 - 1^2) = (4x^2-1)(4x^2+1)\]

Answer 14

by the formula a^2-b^2 = (a+b)(a-b)

Answer 15

and there is more

Answer 16

you see \[4x^2-1 \] can be written as \[(2x)^2-1^2 = (2x+1)(2x-1)\]

Answer 17

so the final answer you get is \[(4x^2+1) (2x+1)(2x-1)\]

Answer 18

which is option B :)

Answer 19

easy,right?

Answer 20

ohhhh im i see what u did

Answer 21

Thanks

Answer 22

yep

Answer 23

welcome