Question

Find dy/dx

Answer 1

\[y = ax + cx^5\]

Answer 2

u know dy/dx is differentiation of y with respect to x
so we have \[\frac{ d }{ dx } (x^n) = n*x^{n-1}\]

Answer 3

so in your equation you have x with powers 1 and 5
and also i forgot to tell you\[\frac{ d }{ dx }(cx) =c \frac{ d }{ dx }(x)\ \ \ where\ c \ is \ constant\]

Answer 4

this differentiation is hard

Answer 5

http://ocw.mit.edu/courses/mathematics/18-01-single-variable-calculus-fall-2006/video-lectures/

Answer 6

they're the lecture videos for first level calculus course at MIT

go thru them if possble

Answer 7

can you explain these 3 more questions than i have 3 questions related to integrals too

Answer 8

http://prntscr.com/3q49os

Answer 9

what is this all about ?
its not good for ur stomach to eat both differentiation and integration in a single meal lol

Answer 10

i have to practice these questions than i have to complete report writing

Answer 11

Okay memorize below rules for differentiation :

Rule 1 :

\(\large \dfrac{d}{dx}\left(c\right) = 0\)

Answer 12

\(\large c\) is constant, like 1, 2, 3 etc..

the derivative of a constant is \(0\)

Answer 13

can you explain the them and their implementation and when to use

Answer 14

Look at ur first problem now

Answer 15

y=b

Answer 16

\(\large y = 100 + b\)

Answer 17

differentiate both sides :

\(\large \dfrac{d}{dx}\left(y\right) = \dfrac{d}{dx} \left(100 + b\right)\)

Answer 18

since \(100\) is a constant, its derivative is \(0\)
since \(b\) is also a constant, its derivative is also \(0\)

Answer 19

\(\large \dfrac{d}{dx}\left(y\right) = \dfrac{d}{dx} \left(100 + b\right)\)

\(\large ~~~~~~~~~~= 0 + 0\)

Answer 20

ok

Answer 21

the answer is simply \(\large 0\)

Answer 22

keep in mind - Only \(x\) and \(y\) are the variables in the given problems. All others are just constants.

Answer 23

are u ready for rule 2 ? :)

Answer 24

yea

Answer 25

before moving to second rule, you need to knw below basic stuff :

\(\large \dfrac{d}{dx} \left(f(x) \color{red}{+} g(x)\right) = \dfrac{d}{dx} \left(f(x)\right) \color{red}{+} \dfrac{d}{dx} \left(g(x)\right) \)


\(\large \dfrac{d}{dx} \left(f(x) \color{red}{-} g(x)\right) = \dfrac{d}{dx} \left(f(x)\right) \color{red}{-} \dfrac{d}{dx} \left(g(x)\right) \)

Answer 26

In words : differentiating `sum of two functions` is same as differentiating `each function separately` and adding them.

Answer 27

similarly,
differentiating `difference of two functions` is same as differentiating `each function separately` and subtracting them.

Answer 28

let me knw once u digest them ^

Answer 29

do u have juice machine in ur home ?

Answer 30

differentiating each function separately. can you explain this statement

Answer 31

ofcourse