I am not getting the answer :/

Question

anonymous · Answer

http://screencast.com/t/hgRWKxh9U8c @Vincent-Lyon.Fr

anonymous · Answer

@ganeshie8

somy · Answer

what is the answer supposed to me?

anonymous · Answer

250W

parthkohli · Answer

Energy dissipated in two seconds:$$E = (2)^2 \cdot 100 + (1)^2 \cdot 100$$$$= 500 \rm J$$
Power dissipated in two seconds:$$P = \dfrac{E}{t} = \rm \dfrac{500 J }{2 sec} = 250 W$$

somy · Answer

why 2 seconds?? @ParthKohli

vincent-lyon.fr · Answer

Instant power is 100.2² = 400 W for half a period, then 100.(-1)² = 100 W for the other half.

The mean power is (400+100)/2 = 250 W

parthkohli · Answer

@Somy The graph is periodic every two seconds.  That's why.

somy · Answer

@ParthKohli how do i know that? i mean it's not written anywhere T_T

somy · Answer

@Vincent-Lyon.Fr oh i was told about this method!!! but i have this tiny question how much is half a period? @thushananth01

somy · Answer

oh lol @ParthKohli  u did same thing but in one go so i didn't really get it, im sorry :P

parthkohli · Answer

half a period = one second

you can see it on the graph

also note that the direction of current doesn't matter

somy · Answer

owh okaaay thnx @ParthKohli  :D

anonymous · Answer

what if the graph is like this
|dw:1402026628221:dw|