Question

Solid xenon hexafluoride is prepared by allowing fluorine gas and xenon gas to react. Write a balanced equation for this reaction. Using this equation, tell me how many grams of xenon are required to form 20.0 g xenon hexafluoride.

Answer 1

Xe (g) + 3 F2 (g) -> XeF6 (s)

Xe does not exist in molecular form.

Calculate molar mass M of XeF6.

Then calculate amount of substance n =m/ M
M = 20 g.

Then you see n(Xe) = n(XeF6).

Mass of Xenon m = n x M(Xe)