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\[\frac{ 6 }{ 5x ^{8} } + \frac{ 4 }{ 3x ^{6} }\]
@ganeshie8
@ranga
@Clueless_math
What is the LCD of \(\Large 5x^8 \text{ and } 3x^6 \ ? \)
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LCD = Least Common Denominator.
@ranga 15x?
It is \(\Large 15x^8\). Multiply top and bottom of each fraction by something so that we get \(\Large 15x^8\) as LCD.
@ranga okay one sec
@ranga so i got 18/5x^8 and 20x^2/15x^8
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\[ \frac{ 6 }{ 5x ^{8} } + \frac{ 4 }{ 3x ^{6} } = \frac{ 6*3}{ 15x ^{8} } + \frac{ 4*5x^2 }{ 15x ^{8} } = \frac{20x^2+18}{15x^8} \] Yes. You have the correct answer!
@ranga yay thank you so much <3
You are welcome. You did good.
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